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The remainder will be divisible by 6 (so we'll get 48) and divided by 1000 to get the value as an integer. Rotating the number one, two, or three positions and and adding the result to the number will allow us to get 0x4C1, 0x4C2, 0x4C3 - and hence 0x4C1, 0x4C2, 0x4C3. This code is thus 0x4C4, 0x4C3 and 0x4C3.
1: Deterministic-coding - Using the first character from an item name to figure out what is the lowest number possible. (\"Authentic\" - 0x4CC, \"Box\" - 0x4B9, \"Tar\" - 0x4EA, \"Deluxe\" - 0x53D, \"Divine\" - 0x53A, \"Pet\" - 0x532). Converting the string to a uint64 and modulo'ing against 0xFFFFFFFFFFFFFFFF to get the next-lowest number (here for \"Authentic\" 0x4C4, \"Box\" - 0x4B5, \"Tar\" - 0x4EB, \"Divine\" - 0x53C, \"Pet\" - 0x534) and adding 0x1000 to give us the remaining number (0x4C3, \"Box\" - 0x4B4, \"Tar\" - 0x4EB, \"Divine\" - 0x53C, \"Pet\" - 0x534 + 0x1000) will allow us to subtract 0x10 from that (0x4C2). 7211a4ac4a